lua code for get the seasons

[B3rt]

Is there a simple lua code i could use to deterime which seaon it is?
So if it is winter, spring, summer or autum (at my location)?

I want to use the season to set some lighting and temp control....

How can i do this simply?

[RichardTSchaefer]

This may help:
   http://www.lua.org/pil/22.1.html

[Brientim]

See http://forum.micasaverde.com/index.php?topic=19596.0

[B3rt]

thx but not really, i still have to make rules to determine which season it is...

I meant more like a app or code like: isSummer() isWinter() isAutum() isSpring() which return me a true or false
Or a code like WhichSeason() which returns the actual season 'spring'...
 

[RexBeckett]

Code: [Select]

function WhichSeason()
     local tNow = os.date("*t")
     local dayofyear = tNow.yday
     local season
     if (dayofyear >= 79) and (dayofyear < 172) then season = "Spring"
     elseif (dayofyear >= 172) and (dayofyear < 266) then season = "Summer"
     elseif (dayofyear >= 266) and (dayofyear < 355) then season = "Autumn"
     else season = "Winter"
     end
     return season
end
Note: This assumes that you are in the Northern hemisphere!
 

[RexBeckett]

Or:

Code: [Select]

function isSpring()
     local tNow = os.date("*t")
     local dayofyear = tNow.yday
     return (dayofyear >= 79) and (dayofyear < 172)
end

function isSummer()
     local tNow = os.date("*t")
     local dayofyear = tNow.yday
     return (dayofyear >= 172) and (dayofyear < 266)
end

function isAutumn()
     local tNow = os.date("*t")
     local dayofyear = tNow.yday
     return (dayofyear >= 266) and (dayofyear < 355)
end

function isWinter()
     local tNow = os.date("*t")
     local dayofyear = tNow.yday
     return (dayofyear >= 355) or (dayofyear < 79)
end
Note: The dayofyear conditions are only appropriate for the Northern hemisphere.